Daily Math Problem - 4/15/20 - Mr. Bowen's Fifth Grade

Daily Math Problem - 4/15/20

4/15/2020

Here is today's math problem from the Learning Menu:

Find a 4-digit number that is divisible by 2, 3, and 5, but NOT divisible by 4.

4 Comments

Haylee

4/15/2020 01:53:09 pm

4110 is divisible by 2 because it is even, 3 because when you add up the numbers it will equal 6 and 6 is divisible by 3, and it is divisible by 5 because it has a zero at the end. Plus it is divisible by 6 because it is even and it is divisible by 3.

Mr. Bowen

4/15/2020 03:31:15 pm

Great explanation, Haylee!

Korbyn

4/15/2020 04:01:49 pm

It has to end in a zero since it is divisible by 5 and 2.
All of the numbers need to add up to something that is divisible by 3.
So I tried 3690, which is not divisible by 4.
Another one could be 3330. Or 6390. Or 3210. But not 1320, as it is divisible by 4.

Mr. Bowen

4/15/2020 04:06:02 pm

Excellent, Korbyn! I like how you are explaining each step.

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Daily Math Problem - 4/15/20

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